-10x^2+600x-3588=0

Solution for -10x^2+600x-3588=0 equation:

-10x^2+600x-3588=0

a = -10; b = 600; c = -3588;
Δ = b2-4ac
Δ = 6002-4·(-10)·(-3588)
Δ = 216480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216480}=\sqrt{16*13530}=\sqrt{16}*\sqrt{13530}=4\sqrt{13530}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-4\sqrt{13530}}{2*-10}=\frac{-600-4\sqrt{13530}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+4\sqrt{13530}}{2*-10}=\frac{-600+4\sqrt{13530}}{-20}
$